Wednesday, May 10, 2017

Calculus: Limits

LIMITS
 
 
INTRODUCTION
 
 
 
 
In mathematics, a limit is the value that a function or sequence "approaches" as the input or index approaches some value. Limits are essential to calculus (and mathematical analysis in general) and are used to define continuity, derivatives, and integrals.
 
 
EXPLANATION
 
Suppose f is a real-valued function and c is a real number. Intuitively speaking, the expression
means that f(x) can be made to be as close to L as desired by making x sufficiently close to c. In that case, the above equation can be read as "the limit of f of x, as x approaches c, is L".



EXAMPLE

1. Replacing the value of x by its tendency (when x tends to a number)
(x2 − 1) (x − 1)
Let's work it out for x=1:
(12 − 1) (1 − 1) = (1 − 1) (1 − 1) = 0 0 
 
 
2. Factoring
By factoring (x2−1) into (x−1)(x+1) we get:
 
 limit as x goes to 1 of (x^2-1)/(x-1) = limit as x goes to 1 of (x+1)
  
Now we can just substitiute x=1 to get the limit:
 limit as x goes to 1 of (x+1) = 1+1 = 2

 

 
3. Conjugate
 
When it's a fraction, multiplying top and bottom by a conjugate might help.
 
limit as goes to 4 of (2-sqrt(x))/(4-x)  Evaluating this at x=4 gives 0/0, which is not a good answer!
So, let's try some rearranging:
Multiply top and bottom by the conjugate of the top: (2-sqrt(x))/(4-x) times (2+sqrt(x))/(2+sqrt(x))
   
Simplify top using (a+b)(a-b) = a^2 - b^2: (2^2-sqrt(x)^2) / (4-x)(2+sqrt(x))
   
Simplify top further: (4-x) / (4-x)(2+sqrt(x))
   
Cancel (4−x) from top and bottom:  1/(2+sqrt(x))
So, now we have:
limit as goes to 4 of (2-sqrt(x))/(4-x) = limit as x goes to 4 of 1/(2+sqrt(x)) = 1/4
 
 
VIDEO
 
 
Here is a video for you to understand better this topic
 

 
 
PRACTICE

 
1.  
[Solution]

2.  
[Solution]

3.  
[Solution]   
 
GOOD LUCK AND HOPE YOU HAVE UNDERSTOOD!!

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